1/2(n-5)-1=2/3n(n-6)

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Solution for 1/2(n-5)-1=2/3n(n-6) equation:



1/2(n-5)-1=2/3n(n-6)
We move all terms to the left:
1/2(n-5)-1-(2/3n(n-6))=0
Domain of the equation: 2(n-5)!=0
n∈R
Domain of the equation: 3n(n-6))!=0
n∈R
We calculate fractions
(3nn/(2(n-5)*3n(n-6)))+(-4nn/(2(n-5)*3n(n-6)))-1=0
We calculate terms in parentheses: +(3nn/(2(n-5)*3n(n-6))), so:
3nn/(2(n-5)*3n(n-6))
We multiply all the terms by the denominator
3nn
Back to the equation:
+(3nn)
We calculate terms in parentheses: +(-4nn/(2(n-5)*3n(n-6))), so:
-4nn/(2(n-5)*3n(n-6))
We multiply all the terms by the denominator
-4nn
Back to the equation:
+(-4nn)
We get rid of parentheses
3nn-4nn-1=0
We move all terms containing n to the left, all other terms to the right
3nn-4nn=1

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