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1/2(n-8)=1/4(n-2)
We move all terms to the left:
1/2(n-8)-(1/4(n-2))=0
Domain of the equation: 2(n-8)!=0
n∈R
Domain of the equation: 4(n-2))!=0We calculate fractions
n∈R
(4nn/(2(n-8)*4(n-2)))+(-2nn/(2(n-8)*4(n-2)))=0
We calculate terms in parentheses: +(4nn/(2(n-8)*4(n-2))), so:
4nn/(2(n-8)*4(n-2))
We multiply all the terms by the denominator
4nn
Back to the equation:
+(4nn)
We calculate terms in parentheses: +(-2nn/(2(n-8)*4(n-2))), so:We get rid of parentheses
-2nn/(2(n-8)*4(n-2))
We multiply all the terms by the denominator
-2nn
Back to the equation:
+(-2nn)
4nn-2nn=0
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