1/2(s-12)=1/4(s+16)

Solution for 1/2(s-12)=1/4(s+16) equation:

1/2(s-12)=1/4(s+16)

We move all terms to the left:

1/2(s-12)-(1/4(s+16))=0


Domain of the equation: 2(s-12)!=0

s∈R



Domain of the equation: 4(s+16))!=0

s∈R


We calculate fractions


(4ss/(2(s-12)*4(s+16)))+(-2ss/(2(s-12)*4(s+16)))=0


We calculate terms in parentheses: +(4ss/(2(s-12)*4(s+16))), so:

4ss/(2(s-12)*4(s+16))

We multiply all the terms by the denominator


4ss

Back to the equation:

+(4ss)



We calculate terms in parentheses: +(-2ss/(2(s-12)*4(s+16))), so:

-2ss/(2(s-12)*4(s+16))

We multiply all the terms by the denominator


-2ss

Back to the equation:

+(-2ss)


We get rid of parentheses

4ss-2ss=0