1/2(s-12)=11/4(s+16)

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Solution for 1/2(s-12)=11/4(s+16) equation:



1/2(s-12)=11/4(s+16)
We move all terms to the left:
1/2(s-12)-(11/4(s+16))=0
Domain of the equation: 2(s-12)!=0
s∈R
Domain of the equation: 4(s+16))!=0
s∈R
We calculate fractions
(4ss/(2(s-12)*4(s+16)))+(-22ss/(2(s-12)*4(s+16)))=0
We calculate terms in parentheses: +(4ss/(2(s-12)*4(s+16))), so:
4ss/(2(s-12)*4(s+16))
We multiply all the terms by the denominator
4ss
Back to the equation:
+(4ss)
We calculate terms in parentheses: +(-22ss/(2(s-12)*4(s+16))), so:
-22ss/(2(s-12)*4(s+16))
We multiply all the terms by the denominator
-22ss
Back to the equation:
+(-22ss)
We get rid of parentheses
4ss-22ss=0

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