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1/2(t+2)=1/3(t-4)
We move all terms to the left:
1/2(t+2)-(1/3(t-4))=0
Domain of the equation: 2(t+2)!=0
t∈R
Domain of the equation: 3(t-4))!=0We calculate fractions
t∈R
(3tt/(2(t+2)*3(t-4)))+(-2tt/(2(t+2)*3(t-4)))=0
We calculate terms in parentheses: +(3tt/(2(t+2)*3(t-4))), so:
3tt/(2(t+2)*3(t-4))
We multiply all the terms by the denominator
3tt
Back to the equation:
+(3tt)
We calculate terms in parentheses: +(-2tt/(2(t+2)*3(t-4))), so:We get rid of parentheses
-2tt/(2(t+2)*3(t-4))
We multiply all the terms by the denominator
-2tt
Back to the equation:
+(-2tt)
3tt-2tt=0
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