1/2(x)+10=x-6

Solution for 1/2(x)+10=x-6 equation:

1/2(x)+10=x-6

We move all terms to the left:

1/2(x)+10-(x-6)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We get rid of parentheses

1/2x-x+6+10=0

We multiply all the terms by the denominator


-x*2x+6*2x+10*2x+1=0

Wy multiply elements

-2x^2+12x+20x+1=0

We add all the numbers together, and all the variables

-2x^2+32x+1=0

a = -2; b = 32; c = +1;
Δ = b2-4ac
Δ = 322-4·(-2)·1
Δ = 1032
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1032}=\sqrt{4*258}=\sqrt{4}*\sqrt{258}=2\sqrt{258}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-2\sqrt{258}}{2*-2}=\frac{-32-2\sqrt{258}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+2\sqrt{258}}{2*-2}=\frac{-32+2\sqrt{258}}{-4}
$