1/2(x+1)+1/4(x+4)=1/6(x-1)

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Solution for 1/2(x+1)+1/4(x+4)=1/6(x-1) equation: 



1/2(x+1)+1/4(x+4)=1/6(x-1)

We move all terms to the left:

1/2(x+1)+1/4(x+4)-(1/6(x-1))=0



Domain of the equation: 2(x+1)!=0

x∈R





Domain of the equation: 4(x+4)!=0

x∈R





Domain of the equation: 6(x-1))!=0

x∈R



We calculate fractions


(-8x^2x/(2(x+1)*4(x+4)*6(x-1)))+(24x^2x/(2(x+1)*4(x+4)*6(x-1)))+(12x^2x/(2(x+1)*4(x+4)*6(x-1)))=0



We calculate terms in parentheses: +(-8x^2x/(2(x+1)*4(x+4)*6(x-1))), so:

-8x^2x/(2(x+1)*4(x+4)*6(x-1))

We multiply all the terms by the denominator


-8x^2x

Back to the equation:

+(-8x^2x)





We calculate terms in parentheses: +(24x^2x/(2(x+1)*4(x+4)*6(x-1))), so:

24x^2x/(2(x+1)*4(x+4)*6(x-1))

We multiply all the terms by the denominator


24x^2x

Back to the equation:

+(24x^2x)





We calculate terms in parentheses: +(12x^2x/(2(x+1)*4(x+4)*6(x-1))), so:

12x^2x/(2(x+1)*4(x+4)*6(x-1))

We multiply all the terms by the denominator


12x^2x

Back to the equation:

+(12x^2x)



We get rid of parentheses

-8x^2x+24x^2x+12x^2x=0

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