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1/2(x+2)+1/2(x+x)=x+2
We move all terms to the left:
1/2(x+2)+1/2(x+x)-(x+2)=0
Domain of the equation: 2(x+2)!=0
x∈R
Domain of the equation: 2(x+x)!=0We add all the numbers together, and all the variables
x∈R
1/2(x+2)+1/2(+2x)-(x+2)=0
We get rid of parentheses
1/2(x+2)+1/2(+2x)-x-2=0
We calculate fractions
-x+(2x(+)/(2(x+2)*2(+2x))+(2xx/(2(x+2)*2(+2x))-2=0
We can not solve this equation
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