1/2(x+2)=1/8(x-1)

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Solution for 1/2(x+2)=1/8(x-1) equation: 



1/2(x+2)=1/8(x-1)

We move all terms to the left:

1/2(x+2)-(1/8(x-1))=0



Domain of the equation: 2(x+2)!=0

x∈R





Domain of the equation: 8(x-1))!=0

x∈R



We calculate fractions


(8xx/(2(x+2)*8(x-1)))+(-2xx/(2(x+2)*8(x-1)))=0



We calculate terms in parentheses: +(8xx/(2(x+2)*8(x-1))), so:

8xx/(2(x+2)*8(x-1))

We multiply all the terms by the denominator


8xx

Back to the equation:

+(8xx)





We calculate terms in parentheses: +(-2xx/(2(x+2)*8(x-1))), so:

-2xx/(2(x+2)*8(x-1))

We multiply all the terms by the denominator


-2xx

Back to the equation:

+(-2xx)



We get rid of parentheses

8xx-2xx=0

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