1/2(x+2)=2/3(x-4)

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Solution for 1/2(x+2)=2/3(x-4) equation:



1/2(x+2)=2/3(x-4)
We move all terms to the left:
1/2(x+2)-(2/3(x-4))=0
Domain of the equation: 2(x+2)!=0
x∈R
Domain of the equation: 3(x-4))!=0
x∈R
We calculate fractions
(3xx/(2(x+2)*3(x-4)))+(-4xx/(2(x+2)*3(x-4)))=0
We calculate terms in parentheses: +(3xx/(2(x+2)*3(x-4))), so:
3xx/(2(x+2)*3(x-4))
We multiply all the terms by the denominator
3xx
Back to the equation:
+(3xx)
We calculate terms in parentheses: +(-4xx/(2(x+2)*3(x-4))), so:
-4xx/(2(x+2)*3(x-4))
We multiply all the terms by the denominator
-4xx
Back to the equation:
+(-4xx)
We get rid of parentheses
3xx-4xx=0

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