1/2(x+2)=2/3(x-4)

Solution for 1/2(x+2)=2/3(x-4) equation:

1/2(x+2)=2/3(x-4)

We move all terms to the left:

1/2(x+2)-(2/3(x-4))=0


Domain of the equation: 2(x+2)!=0

x∈R



Domain of the equation: 3(x-4))!=0

x∈R


We calculate fractions


(3xx/(2(x+2)*3(x-4)))+(-4xx/(2(x+2)*3(x-4)))=0


We calculate terms in parentheses: +(3xx/(2(x+2)*3(x-4))), so:

3xx/(2(x+2)*3(x-4))

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)



We calculate terms in parentheses: +(-4xx/(2(x+2)*3(x-4))), so:

-4xx/(2(x+2)*3(x-4))

We multiply all the terms by the denominator


-4xx

Back to the equation:

+(-4xx)


We get rid of parentheses

3xx-4xx=0