1/2(x+3)+2(x-4)=1/3(x-3)

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Solution for 1/2(x+3)+2(x-4)=1/3(x-3) equation: 



1/2(x+3)+2(x-4)=1/3(x-3)

We move all terms to the left:

1/2(x+3)+2(x-4)-(1/3(x-3))=0



Domain of the equation: 2(x+3)!=0

x∈R





Domain of the equation: 3(x-3))!=0

x∈R



We multiply parentheses

1/2(x+3)+2x-(1/3(x-3))-8=0

We calculate fractions


2x+(3xx/(2(x+3)*3(x-3)))+(-2xx/(2(x+3)*3(x-3)))-8=0



We calculate terms in parentheses: +(3xx/(2(x+3)*3(x-3))), so:

3xx/(2(x+3)*3(x-3))

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)





We calculate terms in parentheses: +(-2xx/(2(x+3)*3(x-3))), so:

-2xx/(2(x+3)*3(x-3))

We multiply all the terms by the denominator


-2xx

Back to the equation:

+(-2xx)



We get rid of parentheses

2x+3xx-2xx-8=0

We move all terms containing x to the left, all other terms to the right

2x+3xx-2xx=8

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