1/2(x+3)-1/2x=1/(x+3

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Solution for 1/2(x+3)-1/2x=1/(x+3 equation: 



1/2(x+3)-1/2x=1/(x+3

We move all terms to the left:

1/2(x+3)-1/2x-(1/(x+3)=0



Domain of the equation: 2(x+3)!=0

x∈R





Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R





Domain of the equation: (x+3)!=0

We move all terms containing x to the left, all other terms to the right

x!=-3

x∈R



We calculate fractions


(2x^2*()/(2(x+3)*2x*(x+3))+(-2x^2x/(2(x+3)*2x*(x+3))+(-(1*2(x+3)*2x)/(2(x+3)*2x*(x+3))=0



We calculate terms in parentheses: +(2x^2*()/(2(x+3)*2x*(x+3))+(-2x^2x/(2(x+3)*2x*(x+3))+(-(1*2(x+3)*2x)/(2(x+3)*2x*(x+3)), so:

2x^2*()/(2(x+3)*2x*(x+3))+(-2x^2x/(2(x+3)*2x*(x+3))+(-(1*2(x+3)*2x)/(2(x+3)*2x*(x+3)

We can not solve this equation

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