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1/2(x+3)=1/3(3x-6)
We move all terms to the left:
1/2(x+3)-(1/3(3x-6))=0
Domain of the equation: 2(x+3)!=0
x∈R
Domain of the equation: 3(3x-6))!=0We calculate fractions
x∈R
(3x3/(2(x+3)*3(3x-6)))+(-2xx/(2(x+3)*3(3x-6)))=0
We calculate terms in parentheses: +(3x3/(2(x+3)*3(3x-6))), so:
3x3/(2(x+3)*3(3x-6))
We multiply all the terms by the denominator
3x3
We add all the numbers together, and all the variables
3x^3
We do not support expression: x^3
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