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1/2(x+3)=1/4(2x+6)
We move all terms to the left:
1/2(x+3)-(1/4(2x+6))=0
Domain of the equation: 2(x+3)!=0
x∈R
Domain of the equation: 4(2x+6))!=0We calculate fractions
x∈R
(4x2/(2(x+3)*4(2x+6)))+(-2xx/(2(x+3)*4(2x+6)))=0
We calculate terms in parentheses: +(4x2/(2(x+3)*4(2x+6))), so:
4x2/(2(x+3)*4(2x+6))
We multiply all the terms by the denominator
4x2
We add all the numbers together, and all the variables
4x^2
Back to the equation:
+(4x^2)
We calculate terms in parentheses: +(-2xx/(2(x+3)*4(2x+6))), so:We get rid of parentheses
-2xx/(2(x+3)*4(2x+6))
We multiply all the terms by the denominator
-2xx
Back to the equation:
+(-2xx)
4x^2-2xx=0
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