1/2(x+4)-2x=3(x-2)-5x-2

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Solution for 1/2(x+4)-2x=3(x-2)-5x-2 equation: 



1/2(x+4)-2x=3(x-2)-5x-2

We move all terms to the left:

1/2(x+4)-2x-(3(x-2)-5x-2)=0



Domain of the equation: 2(x+4)!=0

x∈R



We add all the numbers together, and all the variables

-2x+1/2(x+4)-(3(x-2)-5x-2)=0

We multiply all the terms by the denominator


-2x*2(x+4)-((3(x-2)-5x-2))*2(x+4)+1=0



We calculate terms in parentheses: -((3(x-2)-5x-2))*2(x+4), so:

(3(x-2)-5x-2))*2(x+4



Wy multiply elements

-4x^2(x-((3(x-2)-5x-2))*2(x+4)+1=0

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