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1/2(x+4)=1/2(3x+9)
We move all terms to the left:
1/2(x+4)-(1/2(3x+9))=0
Domain of the equation: 2(x+4)!=0
x∈R
Domain of the equation: 2(3x+9))!=0We calculate fractions
x∈R
(2x3/(2(x+4)*2(3x+9)))+(-2xx/(2(x+4)*2(3x+9)))=0
We calculate terms in parentheses: +(2x3/(2(x+4)*2(3x+9))), so:
2x3/(2(x+4)*2(3x+9))
We multiply all the terms by the denominator
2x3
We add all the numbers together, and all the variables
2x^3
We do not support expression: x^3
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