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1/2(x+4)=2+.5x
We move all terms to the left:
1/2(x+4)-(2+.5x)=0
Domain of the equation: 2(x+4)!=0We add all the numbers together, and all the variables
x∈R
1/2(x+4)-(.5x+2)=0
We get rid of parentheses
1/2(x+4)-.5x-2=0
We multiply all the terms by the denominator
-(.5x)*2(x+4)-2*2(x+4)+1=0
We add all the numbers together, and all the variables
-(+.5x)*2(x+4)-2*2(x+4)+1=0
Wy multiply elements
-(+.5x)*2(x+4)-4x(x+1=0
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