1/2(x+5)(x+7)=35

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Solution for 1/2(x+5)(x+7)=35 equation: 


x in (-oo:+oo)

(1/2)*(x+5)*(x+7) = 35 // - 35

(1/2)*(x+5)*(x+7)-35 = 0

1/2*(x+5)*(x+7)-35 = 0

1/2*(x+5)*(x+7)-35 = 0

1/2*x^2+6*x-35/2 = 0

1/2*x^2+6*x-35/2 = 0

1/2*x^2+6*x-35/2 = 0

DELTA = 6^2-(-35/2*1/2*4)

DELTA = 71

DELTA > 0

x = (71^(1/2)-6)/(1/2*2) or x = (-71^(1/2)-6)/(1/2*2)

x = 71^(1/2)-6 or x = -(71^(1/2)+6)

(x+71^(1/2)+6)*(x-71^(1/2)+6) = 0

(x+71^(1/2)+6)*(x-71^(1/2)+6) = 0

( x+71^(1/2)+6 )

x+71^(1/2)+6 = 0 // - 71^(1/2)+6

x = -(71^(1/2)+6)

( x-71^(1/2)+6 )

x-71^(1/2)+6 = 0 // - 6-71^(1/2)

x = -(6-71^(1/2))

x = 71^(1/2)-6

x in { -(71^(1/2)+6), 71^(1/2)-6 }

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