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1/2(x+8)=1/3(x-9)
We move all terms to the left:
1/2(x+8)-(1/3(x-9))=0
Domain of the equation: 2(x+8)!=0
x∈R
Domain of the equation: 3(x-9))!=0We calculate fractions
x∈R
(3xx/(2(x+8)*3(x-9)))+(-2xx/(2(x+8)*3(x-9)))=0
We calculate terms in parentheses: +(3xx/(2(x+8)*3(x-9))), so:
3xx/(2(x+8)*3(x-9))
We multiply all the terms by the denominator
3xx
Back to the equation:
+(3xx)
We calculate terms in parentheses: +(-2xx/(2(x+8)*3(x-9))), so:We get rid of parentheses
-2xx/(2(x+8)*3(x-9))
We multiply all the terms by the denominator
-2xx
Back to the equation:
+(-2xx)
3xx-2xx=0
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