1/2(x-1)+2x=2/3(x+2)

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Solution for 1/2(x-1)+2x=2/3(x+2) equation: 



1/2(x-1)+2x=2/3(x+2)

We move all terms to the left:

1/2(x-1)+2x-(2/3(x+2))=0



Domain of the equation: 2(x-1)!=0

x∈R





Domain of the equation: 3(x+2))!=0

x∈R



We add all the numbers together, and all the variables

2x+1/2(x-1)-(2/3(x+2))=0

We calculate fractions


2x+(3xx/(2(x-1)*3(x+2)))+(-4xx/(2(x-1)*3(x+2)))=0



We calculate terms in parentheses: +(3xx/(2(x-1)*3(x+2))), so:

3xx/(2(x-1)*3(x+2))

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)





We calculate terms in parentheses: +(-4xx/(2(x-1)*3(x+2))), so:

-4xx/(2(x-1)*3(x+2))

We multiply all the terms by the denominator


-4xx

Back to the equation:

+(-4xx)



We get rid of parentheses

2x+3xx-4xx=0

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