1/2(x-10)=3/4(x+20)

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Solution for 1/2(x-10)=3/4(x+20) equation: 



1/2(x-10)=3/4(x+20)

We move all terms to the left:

1/2(x-10)-(3/4(x+20))=0



Domain of the equation: 2(x-10)!=0

x∈R





Domain of the equation: 4(x+20))!=0

x∈R



We calculate fractions


(4xx/(2(x-10)*4(x+20)))+(-6xx/(2(x-10)*4(x+20)))=0



We calculate terms in parentheses: +(4xx/(2(x-10)*4(x+20))), so:

4xx/(2(x-10)*4(x+20))

We multiply all the terms by the denominator


4xx

Back to the equation:

+(4xx)





We calculate terms in parentheses: +(-6xx/(2(x-10)*4(x+20))), so:

-6xx/(2(x-10)*4(x+20))

We multiply all the terms by the denominator


-6xx

Back to the equation:

+(-6xx)



We get rid of parentheses

4xx-6xx=0

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