1/2(x-10)=31+5x

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Solution for 1/2(x-10)=31+5x equation: 



1/2(x-10)=31+5x

We move all terms to the left:

1/2(x-10)-(31+5x)=0



Domain of the equation: 2(x-10)!=0

x∈R



We add all the numbers together, and all the variables

1/2(x-10)-(5x+31)=0

We get rid of parentheses

1/2(x-10)-5x-31=0

We multiply all the terms by the denominator


-5x*2(x-10)-31*2(x-10)+1=0

Wy multiply elements

-10x^2(x-62x(x+1=0

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