1/2(x-2)=2(x-1/2)

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Solution for 1/2(x-2)=2(x-1/2) equation: 



1/2(x-2)=2(x-1/2)

We move all terms to the left:

1/2(x-2)-(2(x-1/2))=0



Domain of the equation: 2(x-2)!=0

x∈R



We add all the numbers together, and all the variables

1/2(x-2)-(2(+x-1/2))=0

We calculate fractions


()/2x+(-(2(+x-1*2(x-2))/2x=0

We multiply all the terms by the denominator


(-(2(+x-1*2(x-2))+()=0



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We calculate terms in parentheses: +(-(2(+x-1*2(x-2))+(), so:

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We calculate terms in parentheses: +(-(2(+x-1*2(x-2))+(), so:

-(2(+x-1*2(x-2))+(





We calculate terms in parentheses: +(-(2(+x-1*2(x-2))+(), so:

-(2(+x-1*2(x-2))+(





We calculate terms in parentheses: +(-(2(+x-1*2(x-2))+(), so:

-(2(+x-1*2(x-2))+(





We calculate terms in parentheses: +(-(2(+x-1*2(x-2))+(), so:

-(2(+x-1*2(x-2))+(





We calculate terms in parentheses: +(-(2(+x-1*2(x-2))+(), so:

-(2(+x-1*2(x-2))+(





We calculate terms in parentheses: +(-(2(+x-1*2(x-2))+(), so:

-(2(+x-1*2(x-2))+(





We calculate terms in parentheses: +(-(2(+x-1*2(x-2))+(), so:

-(2(+x-1*2(x-2))+(





We calculate terms in parentheses: +(-(2(+x-1*2(x-2))+(), so:

-(2(+x-1*2(x-2))+(





We calculate terms in parentheses: +(-(2(+x-1*2(x-2))+(), so:

-(2(+x-1*2(x-2))+(





We calculate terms in parentheses: +(-(2(+x-1*2(x-2))+(), so:

-(2(+x-1*2(x-2))+(





We calculate terms in parentheses: +(-(2(+x-1*2(x-2))+(), so:

-(2(+x-1*2(x-2))+(





We calculate terms in parentheses: +(-(2(+x-1*2(x-2))+(), so:

-(2(+x-1*2(x-2))+(





We calculate terms in parentheses: +(-(2(+x-1*2(x-2))+(), so:

-(2(+x-1*2(x-2))+(





We calculate terms in parentheses: +(-(2(+x-1*2(x-2))+(), so:

-(2(+x-1*2(x-2))+(





We calculate terms in parentheses: +(-(2(+x-1*2(x-2))+(), so:

-(2(+x-1*2(x-2))+(





We calculate terms in parentheses: +(-(2(+x-1*2(x-2))+(), so:

-(2(+x-1*2(x-2))+(





We calculate terms in parentheses: +(-(2(+x-1*2(x-2))+(), so:

-(2(+x-1*2(x-2))+(





We calculate terms in parentheses: +(-(2(+x-1*2(x-2))+(), so:

-(2(+x-1*2(x-2))+(





We calculate terms in parentheses: +(-(2(+x-1*2(x-2))+(), so:

-(2(+x-1*2(x-2))+(





We calculate terms in parentheses: +(-(2(+x-1*2(x-2))+(), so:

-(2(+x-1*2(x-2))+(





We calculate terms in parentheses: +(-(2(+x-1*2(x-2))+(), so:

-(2(+x-1*2(x-2))+(

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