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1/2(x-2)=4/3(x+8)
We move all terms to the left:
1/2(x-2)-(4/3(x+8))=0
Domain of the equation: 2(x-2)!=0
x∈R
Domain of the equation: 3(x+8))!=0We calculate fractions
x∈R
(3xx/(2(x-2)*3(x+8)))+(-8xx/(2(x-2)*3(x+8)))=0
We calculate terms in parentheses: +(3xx/(2(x-2)*3(x+8))), so:
3xx/(2(x-2)*3(x+8))
We multiply all the terms by the denominator
3xx
Back to the equation:
+(3xx)
We calculate terms in parentheses: +(-8xx/(2(x-2)*3(x+8))), so:We get rid of parentheses
-8xx/(2(x-2)*3(x+8))
We multiply all the terms by the denominator
-8xx
Back to the equation:
+(-8xx)
3xx-8xx=0
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