1/2(x-3)+1/3(x+1)=8

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Solution for 1/2(x-3)+1/3(x+1)=8 equation: 



1/2(x-3)+1/3(x+1)=8

We move all terms to the left:

1/2(x-3)+1/3(x+1)-(8)=0



Domain of the equation: 2(x-3)!=0

x∈R





Domain of the equation: 3(x+1)!=0

x∈R



We calculate fractions


(3xx/(2(x-3)*3(x+1))+(2xx/(2(x-3)*3(x+1))-8=0

We can not solve this equation

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