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1/2(x-3)-2(x+1)=5
We move all terms to the left:
1/2(x-3)-2(x+1)-(5)=0
Domain of the equation: 2(x-3)!=0We multiply parentheses
x∈R
1/2(x-3)-2x-2-5=0
We multiply all the terms by the denominator
-2x*2(x-3)-2*2(x-3)-5*2(x-3)+1=0
Wy multiply elements
-4x^2(x-4x(x-10x(x+1=0
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