1/2(x-3)2+4

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Solution for 1/2(x-3)2+4 equation: 


x in (-oo:+oo)

(1/2)*(x-3)^2+4 = 0

1/2*(x-3)^2+4 = 0

1/2*(x-3)^2+4 = 0

1/2*x^2-3*x+17/2 = 0

1/2*x^2-3*x+17/2 = 0

1/2*x^2-3*x+17/2 = 0

DELTA = (-3)^2-(1/2*4*17/2)

DELTA = -8

DELTA < 0

1 = 0

1 = 0

x belongs to the empty set

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