1/2(x-3)=1/3(2x+1)

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Solution for 1/2(x-3)=1/3(2x+1) equation: 



1/2(x-3)=1/3(2x+1)

We move all terms to the left:

1/2(x-3)-(1/3(2x+1))=0



Domain of the equation: 2(x-3)!=0

x∈R





Domain of the equation: 3(2x+1))!=0

x∈R



We calculate fractions


(3x2/(2(x-3)*3(2x+1)))+(-2xx/(2(x-3)*3(2x+1)))=0



We calculate terms in parentheses: +(3x2/(2(x-3)*3(2x+1))), so:

3x2/(2(x-3)*3(2x+1))

We multiply all the terms by the denominator


3x2

We add all the numbers together, and all the variables

3x^2

Back to the equation:

+(3x^2)





We calculate terms in parentheses: +(-2xx/(2(x-3)*3(2x+1))), so:

-2xx/(2(x-3)*3(2x+1))

We multiply all the terms by the denominator


-2xx

Back to the equation:

+(-2xx)



We get rid of parentheses

3x^2-2xx=0

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