1/2(x-3)=2/4(x+1)

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Solution for 1/2(x-3)=2/4(x+1) equation:



1/2(x-3)=2/4(x+1)
We move all terms to the left:
1/2(x-3)-(2/4(x+1))=0
Domain of the equation: 2(x-3)!=0
x∈R
Domain of the equation: 4(x+1))!=0
x∈R
We calculate fractions
(4xx/(2(x-3)*4(x+1)))+(-4xx/(2(x-3)*4(x+1)))=0
We calculate terms in parentheses: +(4xx/(2(x-3)*4(x+1))), so:
4xx/(2(x-3)*4(x+1))
We multiply all the terms by the denominator
4xx
Back to the equation:
+(4xx)
We calculate terms in parentheses: +(-4xx/(2(x-3)*4(x+1))), so:
-4xx/(2(x-3)*4(x+1))
We multiply all the terms by the denominator
-4xx
Back to the equation:
+(-4xx)
We get rid of parentheses
4xx-4xx=0

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