1/2(x-5)(x-14)=35

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Solution for 1/2(x-5)(x-14)=35 equation: 



1/2(x-5)(x-14)=35

We move all terms to the left:

1/2(x-5)(x-14)-(35)=0



Domain of the equation: 2(x-5)(x-14)!=0

x∈R



We multiply parentheses ..

1/2(+x^2-14x-5x+70)-35=0

We multiply all the terms by the denominator


-35*2(+x^2-14x-5x+70)+1=0

Wy multiply elements

-70x(++1=0

We use the square of the difference formula

-70x(+1=0

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