1/2(x-5)+x=17+3(4-x)

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Solution for 1/2(x-5)+x=17+3(4-x) equation:



1/2(x-5)+x=17+3(4-x)
We move all terms to the left:
1/2(x-5)+x-(17+3(4-x))=0
Domain of the equation: 2(x-5)!=0
x∈R
We add all the numbers together, and all the variables
1/2(x-5)+x-(17+3(-1x+4))=0
We add all the numbers together, and all the variables
x+1/2(x-5)-(17+3(-1x+4))=0
We multiply all the terms by the denominator
x*2(x-5)-((17+3(-1x+4)))*2(x-5)+1=0
We calculate terms in parentheses: -((17+3(-1x+4)))*2(x-5), so:
(17+3(-1x+4)))*2(x-5
Wy multiply elements
2x^2(x-((17+3(-1x+4)))*2(x-5)+1=0

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