1/2(x-5)=1/2(5-x)

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Solution for 1/2(x-5)=1/2(5-x) equation: 



1/2(x-5)=1/2(5-x)

We move all terms to the left:

1/2(x-5)-(1/2(5-x))=0



Domain of the equation: 2(x-5)!=0

x∈R





Domain of the equation: 2(5-x))!=0

x∈R



We add all the numbers together, and all the variables

1/2(x-5)-(1/2(-1x+5))=0

We calculate fractions


(2x(-)/(2(x-5)*2(-1x+5)))+(-2xx/(2(x-5)*2(-1x+5)))=0



We calculate terms in parentheses: +(2x(-)/(2(x-5)*2(-1x+5))), so:

2x(-)/(2(x-5)*2(-1x+5))

We add all the numbers together, and all the variables

2x0/(2(x-5)*2(-1x+5))

We multiply all the terms by the denominator


2x0

We add all the numbers together, and all the variables

2x

Back to the equation:

+(2x)





We calculate terms in parentheses: +(-2xx/(2(x-5)*2(-1x+5))), so:

-2xx/(2(x-5)*2(-1x+5))

We multiply all the terms by the denominator


-2xx

Back to the equation:

+(-2xx)



We get rid of parentheses

2x-2xx=0

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