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1/2(x-5)=1/2(x+6)
We move all terms to the left:
1/2(x-5)-(1/2(x+6))=0
Domain of the equation: 2(x-5)!=0
x∈R
Domain of the equation: 2(x+6))!=0We calculate fractions
x∈R
(2xx/(2(x-5)*2(x+6)))+(-2xx/(2(x-5)*2(x+6)))=0
We calculate terms in parentheses: +(2xx/(2(x-5)*2(x+6))), so:
2xx/(2(x-5)*2(x+6))
We multiply all the terms by the denominator
2xx
Back to the equation:
+(2xx)
We calculate terms in parentheses: +(-2xx/(2(x-5)*2(x+6))), so:We get rid of parentheses
-2xx/(2(x-5)*2(x+6))
We multiply all the terms by the denominator
-2xx
Back to the equation:
+(-2xx)
2xx-2xx=0
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