1/2(x-5)=1/6(x+6)

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Solution for 1/2(x-5)=1/6(x+6) equation: 



1/2(x-5)=1/6(x+6)

We move all terms to the left:

1/2(x-5)-(1/6(x+6))=0



Domain of the equation: 2(x-5)!=0

x∈R





Domain of the equation: 6(x+6))!=0

x∈R



We calculate fractions


(6xx/(2(x-5)*6(x+6)))+(-2xx/(2(x-5)*6(x+6)))=0



We calculate terms in parentheses: +(6xx/(2(x-5)*6(x+6))), so:

6xx/(2(x-5)*6(x+6))

We multiply all the terms by the denominator


6xx

Back to the equation:

+(6xx)





We calculate terms in parentheses: +(-2xx/(2(x-5)*6(x+6))), so:

-2xx/(2(x-5)*6(x+6))

We multiply all the terms by the denominator


-2xx

Back to the equation:

+(-2xx)



We get rid of parentheses

6xx-2xx=0

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