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1/2(x-6)-2(3-2x)=6-2(4x+1)
We move all terms to the left:
1/2(x-6)-2(3-2x)-(6-2(4x+1))=0
Domain of the equation: 2(x-6)!=0We add all the numbers together, and all the variables
x∈R
1/2(x-6)-2(-2x+3)-(6-2(4x+1))=0
We multiply parentheses
1/2(x-6)+4x-(6-2(4x+1))-6=0
We multiply all the terms by the denominator
4x*2(x-6)-((6-2(4x+1)))*2(x-6)-6*2(x-6)+1=0
We calculate terms in parentheses: -((6-2(4x+1)))*2(x-6), so:Wy multiply elements
(6-2(4x+1)))*2(x-6
8x^2(x-((6-2(4x+1)))*2(x-6)-12x(x+1=0
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