1/2(x-8)+4=3/4(x+2)

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Solution for 1/2(x-8)+4=3/4(x+2) equation: 



1/2(x-8)+4=3/4(x+2)

We move all terms to the left:

1/2(x-8)+4-(3/4(x+2))=0



Domain of the equation: 2(x-8)!=0

x∈R





Domain of the equation: 4(x+2))!=0

x∈R



We calculate fractions


(4xx/(2(x-8)*4(x+2)))+(-6xx/(2(x-8)*4(x+2)))+4=0



We calculate terms in parentheses: +(4xx/(2(x-8)*4(x+2))), so:

4xx/(2(x-8)*4(x+2))

We multiply all the terms by the denominator


4xx

Back to the equation:

+(4xx)





We calculate terms in parentheses: +(-6xx/(2(x-8)*4(x+2))), so:

-6xx/(2(x-8)*4(x+2))

We multiply all the terms by the denominator


-6xx

Back to the equation:

+(-6xx)



We get rid of parentheses

4xx-6xx+4=0

We move all terms containing x to the left, all other terms to the right

4xx-6xx=-4

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