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1/2(x-8)+4=3/4(x+2)
We move all terms to the left:
1/2(x-8)+4-(3/4(x+2))=0
Domain of the equation: 2(x-8)!=0
x∈R
Domain of the equation: 4(x+2))!=0We calculate fractions
x∈R
(4xx/(2(x-8)*4(x+2)))+(-6xx/(2(x-8)*4(x+2)))+4=0
We calculate terms in parentheses: +(4xx/(2(x-8)*4(x+2))), so:
4xx/(2(x-8)*4(x+2))
We multiply all the terms by the denominator
4xx
Back to the equation:
+(4xx)
We calculate terms in parentheses: +(-6xx/(2(x-8)*4(x+2))), so:We get rid of parentheses
-6xx/(2(x-8)*4(x+2))
We multiply all the terms by the denominator
-6xx
Back to the equation:
+(-6xx)
4xx-6xx+4=0
We move all terms containing x to the left, all other terms to the right
4xx-6xx=-4
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