1/2(y+1)+1/3(y-1)=5/12(y-2)

Solution for 1/2(y+1)+1/3(y-1)=5/12(y-2) equation:

1/2(y+1)+1/3(y-1)=5/12(y-2)

We move all terms to the left:

1/2(y+1)+1/3(y-1)-(5/12(y-2))=0


Domain of the equation: 2(y+1)!=0

y∈R



Domain of the equation: 3(y-1)!=0

y∈R



Domain of the equation: 12(y-2))!=0

y∈R


We calculate fractions


(-30y^2y/(2(y+1)*3(y-1)*12(y-2)))+(36y^2y/(2(y+1)*3(y-1)*12(y-2)))+(24y^2y/(2(y+1)*3(y-1)*12(y-2)))=0


We calculate terms in parentheses: +(-30y^2y/(2(y+1)*3(y-1)*12(y-2))), so:

-30y^2y/(2(y+1)*3(y-1)*12(y-2))

We multiply all the terms by the denominator


-30y^2y

Back to the equation:

+(-30y^2y)



We calculate terms in parentheses: +(36y^2y/(2(y+1)*3(y-1)*12(y-2))), so:

36y^2y/(2(y+1)*3(y-1)*12(y-2))

We multiply all the terms by the denominator


36y^2y

Back to the equation:

+(36y^2y)



We calculate terms in parentheses: +(24y^2y/(2(y+1)*3(y-1)*12(y-2))), so:

24y^2y/(2(y+1)*3(y-1)*12(y-2))

We multiply all the terms by the denominator


24y^2y

Back to the equation:

+(24y^2y)


We get rid of parentheses

-30y^2y+36y^2y+24y^2y=0