1/2(y+4)=1/2(3y-8)

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Solution for 1/2(y+4)=1/2(3y-8) equation: 



1/2(y+4)=1/2(3y-8)

We move all terms to the left:

1/2(y+4)-(1/2(3y-8))=0



Domain of the equation: 2(y+4)!=0

y∈R





Domain of the equation: 2(3y-8))!=0

y∈R



We calculate fractions


(2y3/(2(y+4)*2(3y-8)))+(-2yy/(2(y+4)*2(3y-8)))=0



We calculate terms in parentheses: +(2y3/(2(y+4)*2(3y-8))), so:

2y3/(2(y+4)*2(3y-8))

We multiply all the terms by the denominator


2y3

We add all the numbers together, and all the variables

2y^3

We do not support eypression: y^3

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