1/2(y-2)+3=9y+2

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Solution for 1/2(y-2)+3=9y+2 equation: 



1/2(y-2)+3=9y+2

We move all terms to the left:

1/2(y-2)+3-(9y+2)=0



Domain of the equation: 2(y-2)!=0

y∈R



We get rid of parentheses

1/2(y-2)-9y-2+3=0

We multiply all the terms by the denominator


-9y*2(y-2)-2*2(y-2)+3*2(y-2)+1=0

Wy multiply elements

-18y^2(y-4y(y+6y(y+1=0

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