1/2(y-2)+6=7/8(3y-4)

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Solution for 1/2(y-2)+6=7/8(3y-4) equation: 



1/2(y-2)+6=7/8(3y-4)

We move all terms to the left:

1/2(y-2)+6-(7/8(3y-4))=0



Domain of the equation: 2(y-2)!=0

y∈R





Domain of the equation: 8(3y-4))!=0

y∈R



We calculate fractions


(8y3/(2(y-2)*8(3y-4)))+(-14yy/(2(y-2)*8(3y-4)))+6=0



We calculate terms in parentheses: +(8y3/(2(y-2)*8(3y-4))), so:

8y3/(2(y-2)*8(3y-4))

We multiply all the terms by the denominator


8y3

We add all the numbers together, and all the variables

8y^3

We do not support eypression: y^3

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