1/2(y-6)=1/3(y+1)

Solution for 1/2(y-6)=1/3(y+1) equation:

1/2(y-6)=1/3(y+1)

We move all terms to the left:

1/2(y-6)-(1/3(y+1))=0


Domain of the equation: 2(y-6)!=0

y∈R



Domain of the equation: 3(y+1))!=0

y∈R


We calculate fractions


(3yy/(2(y-6)*3(y+1)))+(-2yy/(2(y-6)*3(y+1)))=0


We calculate terms in parentheses: +(3yy/(2(y-6)*3(y+1))), so:

3yy/(2(y-6)*3(y+1))

We multiply all the terms by the denominator


3yy

Back to the equation:

+(3yy)



We calculate terms in parentheses: +(-2yy/(2(y-6)*3(y+1))), so:

-2yy/(2(y-6)*3(y+1))

We multiply all the terms by the denominator


-2yy

Back to the equation:

+(-2yy)


We get rid of parentheses

3yy-2yy=0