1/2(z+3)=1/2(z-7)

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Solution for 1/2(z+3)=1/2(z-7) equation: 



1/2(z+3)=1/2(z-7)

We move all terms to the left:

1/2(z+3)-(1/2(z-7))=0



Domain of the equation: 2(z+3)!=0

z∈R





Domain of the equation: 2(z-7))!=0

z∈R



We calculate fractions


(2zz/(2(z+3)*2(z-7)))+(-2zz/(2(z+3)*2(z-7)))=0



We calculate terms in parentheses: +(2zz/(2(z+3)*2(z-7))), so:

2zz/(2(z+3)*2(z-7))

We multiply all the terms by the denominator


2zz

Back to the equation:

+(2zz)





We calculate terms in parentheses: +(-2zz/(2(z+3)*2(z-7))), so:

-2zz/(2(z+3)*2(z-7))

We multiply all the terms by the denominator


-2zz

Back to the equation:

+(-2zz)



We get rid of parentheses

2zz-2zz=0

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