1/2(z+3)=1/3(3z-5)

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Solution for 1/2(z+3)=1/3(3z-5) equation: 



1/2(z+3)=1/3(3z-5)

We move all terms to the left:

1/2(z+3)-(1/3(3z-5))=0



Domain of the equation: 2(z+3)!=0

z∈R





Domain of the equation: 3(3z-5))!=0

z∈R



We calculate fractions


(3z3/(2(z+3)*3(3z-5)))+(-2zz/(2(z+3)*3(3z-5)))=0



We calculate terms in parentheses: +(3z3/(2(z+3)*3(3z-5))), so:

3z3/(2(z+3)*3(3z-5))

We multiply all the terms by the denominator


3z3

We add all the numbers together, and all the variables

3z^3

We do not support ezpression: z^3

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