1/2(z+8)=9/z

Solution for 1/2(z+8)=9/z equation:

1/2(z+8)=9/z

We move all terms to the left:

1/2(z+8)-(9/z)=0


Domain of the equation: 2(z+8)!=0

z∈R



Domain of the equation: z)!=0

z!=0/1

z!=0

z∈R


We add all the numbers together, and all the variables

1/2(z+8)-(+9/z)=0

We get rid of parentheses

1/2(z+8)-9/z=0

We calculate fractions


z/(2z^2+16z)+(-18zz/(2z^2+16z)=0


We calculate terms in parentheses: +(-18zz/(2z^2+16z), so:

-18zz/(2z^2+16z

We multiply all the terms by the denominator


-18zz

Back to the equation:

+(-18zz)


We get rid of parentheses

z/(2z^2+16z)-18zz=0

We multiply all the terms by the denominator


z-18zz*(2z^2+16z)=0

We multiply parentheses

-36z^3-288z^2+z=0

We do not support ezpression: z^3