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1/2(5-2h)=h/2
We move all terms to the left:
1/2(5-2h)-(h/2)=0
Domain of the equation: 2(5-2h)!=0We add all the numbers together, and all the variables
h∈R
1/2(-2h+5)-(+h/2)=0
We get rid of parentheses
1/2(-2h+5)-h/2=0
We calculate fractions
=0
h=0/1
h=0
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