1/2*4x*5x=40

Solution for 1/2*4x*5x=40 equation:

1/2*4x*5x=40

We move all terms to the left:

1/2*4x*5x-(40)=0


Domain of the equation: 2*4x*5x!=0

x!=0/1

x!=0

x∈R


We multiply all the terms by the denominator


-40*2*4x*5x+1=0

Wy multiply elements

-1600x^2*4+1=0

Wy multiply elements

-6400x^2+1=0

a = -6400; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-6400)·1
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-160}{2*-6400}=\frac{-160}{-12800}
=1/80
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+160}{2*-6400}=\frac{160}{-12800}
=-1/80
$