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1/2+(3x+3)=2(3-2x)+1
We move all terms to the left:
1/2+(3x+3)-(2(3-2x)+1)=0
We add all the numbers together, and all the variables
(3x+3)-(2(-2x+3)+1)+1/2=0
We get rid of parentheses
3x-(2(-2x+3)+1)+3+1/2=0
We multiply all the terms by the denominator
3x*2-((2(-2x+3)+1))*2+1+3*2=0
We add all the numbers together, and all the variables
3x*2-((2(-2x+3)+1))*2+7=0
Wy multiply elements
6x-((2(-2x+3)+1))*2+7=0
We move all terms containing x to the left, all other terms to the right
6x-((2(-2x+3)+1))*2=-7
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