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1/2+2/5x-1=1/5x+1x
We move all terms to the left:
1/2+2/5x-1-(1/5x+1x)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 5x+1x)!=0We add all the numbers together, and all the variables
x∈R
2/5x-(+x+1/5x)-1+1/2=0
We get rid of parentheses
2/5x-x-1/5x-1+1/2=0
We calculate fractions
-x+()/10x+5x/10x-1=0
We add all the numbers together, and all the variables
-1x+()/10x+5x/10x-1=0
We multiply all the terms by the denominator
-1x*10x+5x-1*10x+()=0
We add all the numbers together, and all the variables
5x-1x*10x-1*10x=0
Wy multiply elements
-10x^2+5x-10x=0
We add all the numbers together, and all the variables
-10x^2-5x=0
a = -10; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·(-10)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*-10}=\frac{0}{-20} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*-10}=\frac{10}{-20} =-1/2 $
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