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1/2+3x=1/3(x-6)
We move all terms to the left:
1/2+3x-(1/3(x-6))=0
Domain of the equation: 3(x-6))!=0We calculate fractions
x∈R
3x+()/6x+(3xx/6x=0
We multiply all the terms by the denominator
3x*6x+(3xx+()=0
We calculate terms in parentheses: +(3xx+(), so:Wy multiply elements
3xx+(
We add all the numbers together, and all the variables
3xx
Back to the equation:
+(3xx)
18x^2+3xx=0
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