1/2-7/2z=5/z

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Solution for 1/2-7/2z=5/z equation: 


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

1/2-((7/2)*z) = 5/z // - 5/z

1/2-((7/2)*z)-(5/z) = 0

(-7/2)*z-5*z^-1+1/2 = 0

1/2*z^0-7/2*z^1-5*z^-1 = 0

(1/2*z^1-7/2*z^2-5*z^0)/(z^1) = 0 // * z^2

z^1*(1/2*z^1-7/2*z^2-5*z^0) = 0

z^1

(-7/2)*z^2+(1/2)*z-5 = 0

(-7/2)*z^2+(1/2)*z-5 = 0

DELTA = (1/2)^2-(-5*4*(-7/2))

DELTA = -279/4

DELTA < 0

z in { } 

z belongs to the empty set

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